(3x^2)-22x=16

Solution for (3x^2)-22x=16 equation:

(3x^2)-22x=16

We move all terms to the left:

(3x^2)-22x-(16)=0

a = 3; b = -22; c = -16;
Δ = b2-4ac
Δ = -222-4·3·(-16)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-26}{2*3}=\frac{-4}{6}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+26}{2*3}=\frac{48}{6}
=8
$